Maharashtra Board Class 10 Science 1 Sample Paper Set 3 with Answers

Maharashtra Board SSC Class 10 Science 1 Sample Paper Set 3 with Answers Solutions Pdf Download.

Maharashtra Board Class 10 Science 1 Model Paper Set 3 with Answers

Time: 2 Hours
Total Marks: 40

Note:

1. All questions are compulsory.
2. Use of a calculator is not allowed.
3. The numbers to the right of the questions indicate full marks.
4. In case of MCQs (Q. No. 1(A)) only the first attempt will be evaluated and will be given credit.
5. For each MCQ, the correct alternative (A), (B), (C) or (D) with subquestion number is to be written as an answer.
   For Eg.: (i) (A), (ii) (B), (iii) (C)
6. Scientifically correct, labelled diagrams should be drawn wherever necessary.

Question 1.
Choose the correct alternative. [5]
i. The IRNSS satellite is used ________. (A)
(A) to get directions of any location on the earth.
(B) to study and forecast weather conditions on the earth.
(C) to establish communication between different locations in the world.
(D) in exploration and management of natural resources.
Answer:
(A) to get directions of any location on the earth.

ii. When electric current is passed through the solenoid, it shows magnetic lines of force similar to a ________. (A)
(A) bar magnet
(B) horse shoe magnet
(C) disk magnet
(D) spherical magnet
Answer:
(A) bar magnet

iii. In which block of the modem periodic table are the nonmetals found? (B)
(A) s-block
(B) p-block
(C) d-block
(D) f-black
Answer:
(B) p-block

iv. At what distance a watch maker must hold his lens from the watch? (B)
(A) At infinity.
(B) At a distance less than the focal length of the lens.
(C) At a distance more than the focal length of the lens.
(D) At zero distance.
Answer:
(B) At a distance less than the focal length of the lens.

v. What will be the weight of a person on earth, who weighs 9 N on the moon? (D)
(A) 3N
(B) 15N
(C) 45 N
(D) 54 N
Answer:
(D) 54 N
(Note: Students are expected to write the correct option in the answer. Example: i. (A))

(B) Answer the following. [5]
i. Find odd one out and write explanation. Lead, gold, ice, iron.
ii. Match the following:

Column I	Column II	Column III
a. Mass	1. m/s2	i. Zero at the centre
b. Weight	2. kg	ii. Measure of inertia
	3. Nm2/kg2	iii. Zero at all places
	4. N	iv. Maximum at the centre

iii. State true or false.
A satellite needs a specific velocity to revolve in a specific orbit.
iv. Complete the analogy.
In Fleming’s right hand rule-Thumb: Motion of conductor :: In Fleming’s right’hand rule-index finger: ________
v. Name the reagent that dissolves noble metals.
Answer:
i. Ice
All other substances expand on heating while ice contracts on heating.
(Note: In ’Find the odd one out’, students are expected to identify the odd one out of 4-5 components. Students must give an appropriate explanation, only if asked in the question.)

ii.

Column I	Column II	Column III
a. Mass	2. kg	ii. Measure of inertia
b. Weight	4. N	i. Zero at the centre

(Note: In ‘Match the column’ students are expected to match the contents of Column I, with those in Column II and Column III appropriately, and write the answer in a tabular format.)

iii. True
(Note: In ‘True or false’, students are expected to mention whether the sentence is true or false; Students must write the correct statement, only if asked in the question.)

iv. In Fleming’s right hand rule-Thumb : Motion of conductor :: In Fleming’s right hand rule-index finger : Magnetic field
(Note: In ’Find the correlation/ Complete the analogy’, students are expected to identify the correlation between two components and rewrite it. Students must give an appropriate explanation, only if asked in the question.)

v. Aqua regia
(Note: In ‘Name the following/Identify’ students are expected to identify and write only the term and not the complete statement.)

Question 2.
(A) Give scientific reasons. (Attempt any 2) [4]
i. Metallic character goes on decreasing while going from left to right in a period.
ii. Why is tungsten metal used to make a solenoid type coil in an electric bulb?
iii. In cold regions in winter, the rocks crack due to anomalous expansion of water.
(B) Answer the following. (Attempt any 3) [4]
i. What are the physical properties of metals?
ii. Distinguish between farsightedness and nearsightedness.
iii. Equal heat is given to two objects A and B of mass 5 g. Temperature of A increases by 1°C and B by 3°C. Which object has more specific heat? And by what factor?
iv. Complete the table.

v. Identify the type of the following reactions of carbon compounds.
a. CH₃ – CH₃ + Cl₂ → CH₃ – CH₂ – Cl + HCl
b. CH₃ – COOH + CH₃ – OH → CH₃ – COO – CH₃ + H₂O
Answer:
(A)
i. a. While going from left to right in a period, electrons are added to the same outermost shell. At the same time, protons get added in the nucleus increasing the nuclear charge. Hence, these electrons experience greater pull from the nucleus due to increased effective nuclear charge.
b. As a result, it becomes difficult to remove a valence electron from the atom. Hence, metallic character goes on decreasing while going from left to right in a period.

ii. a. Electric bulb works on the principle of heating effect electric of current.
b. The solenoid type coil of bulb has high resistivity and very high melting point.
c. When current is passed through the bulb, solenoid type coil of bulb gets heated to high temperature (upto 3400 °C) and starts glowing.
Hence, tungsten metal is used to make a solenoid type coil in an electric bulb.

iii. a. When water is accumulated in a fissure of a rock, as temperature in cold climate dips below 4 °C, water starts expanding instead of contracting.
b. Between temperature fall of 4 °C to 0 °C, volume of water increases continuously due to anomalous behaviour of water.
c. At the same time, rocks undergo contraction.
d. As a result, rocks experience force applied by water and crack.

(B) i. Physical properties of metals:
a. They are ductile and malleable.
b. They are good conductors of heat and electricity.
c. They are lustrous.
d. They are sonorous.
e. They are hard (except lithium, sodium, potassium).
f. They have high melting and boiling points (except sodium, potassium, mercury, gallium). [Any four points]
(Note: In ‘Write properties/characteristics/uses/advantages/effects’, students are expected to write minimum 4 points.)

ii.

Farsightedness	Nearsightedness
a. This problem arises due to slight flattening of the eyeball.	This problem arises due to slight elongation of the eyeball.
b. The curvature of the cornea and eye lens decreases so that the converging power becomes less.	The curvature of the cornea and eye lens increases so that the converging power becomes more.
c. The distance between the eye lens and the retina decreases.	The distance between the eye lens and the retina increases.
d. The near point of the eye shifts farther away from the eye.	The far point of the eye shifts closer to eye.
e. A person suffering from this defect can see distant objects clearly but is unable to see nearby objects.	A person suffering from this defect can see nearby objects clearly but is unable to see distant objects.
f. It can be corrected by using spectacles having convex lenses of suitable focal length.	It can be corrected by using spectacles having concave lenses of suitable focal length.

[Any four points]
(Note: In ‘Write the difference/ Distinguish’, students are expected to write minimum 4 independent points of differences between two components, in a tabular format.)

iii. Solution:
Heat absorbed by object A(Q_A) = m_A c_A ∆T_A
Heat absorbed by object B(Q_B) = m_B C_B ∆T_B
Given: Q_A = Q_B and m_A = m_B = 5 g.
Also, ∆T_A = 1 °C and ∆T_B = 3 °C
∴ C_A∆T_A – C_B∆T_B
∴ C_A = 3C_B
Ans: This implies object A has more specific heat than object B by factor of 3.

iv.

(Note: In ‘Complete the flowchart/ table, students are expected to fill in the blanks with appropriate answers and redraw the f lowchart/ table.)

v. a. Substitution reaction
b. Esterif ication reaction

Question 3.
Answer the following. (Attempt any 5) [15]
i. Study the following experimental set-up and answer the following questions.

a. What changes will you observe in test tube A?
b. What do you think will happen in test tube B?
c. What will happen if copper sulphate solution in test tube A is replaced by magnesium nitrate solution?
ii. An electrical iron uses a power of 1100 W when set to higher temperature. If set to lower temperature, it uses 330 W power. Find out the electric current and the respective resistances for the two settings. The iron is connected to a potential difference of 220 V.
iii. How are the satellites classified based on their functions?
iv. Select the appropriate options and complete the following paragraph.
(oxygen, hydrogen, reduction, oxidation, never, always, redox, decomposition)
________ is the process in which a substance gains ________ or loses hydrogen. ________ is the process in which a substance gains ________ or loses oxygen. The reaction in which one reactant gets oxidised and the other reactant gets reduced is called as oxidation-reduction reaction or________reaction. Oxidation and reduction reactions ________ occur simultaneously.
v. A stone thrown vertically upwards with initial velocity ‘u’ reaches a height ‘IT before coming down. Show that the time taken to go up is same as the time taken to come down.
vi. Complete the following table:

vii. Observe the following picture and write down the chemical reaction with explanation.

viii. Identify concept in given statements.
a. Rays travelling parallel to principal axis falling on lens come together. Identify the type of lens.
b. For a given lens, ratio of height of image to the height of object is calculated. What is the ratio defined as?
c. Reema’s eyes are black while Rahul’s eyes are brown in colour. Which part of eye decides colour of eyes?
d. Priya’s grandfather is prescribed bifocal lens as focusing power of his eye lens has decreased with age. Name the defect of vision is he suffering from.
e. Which(optical device is used to see distant stars and planets in their magnified form?
f. Name the phenomenon that causes image to remain imprinted on retina for — of a second after the removal of object in front of the eyes.
Answer:
i. a. The blue colour of the solution will turn to green in test tube A and copper coating will form on iron rail.
b. The reaction will not occur in test tube B because iron is more reactive than copper.
c. If copper sulphate solution in test tube A is replaced by magnesium nitrate solution then reaction will not occur as magnesium is more reactive than iron.

ii. Solution:
Given: Potential difference (V) = 220 V,
Power used at higher temperature (P₁) = 1100 W,
Power used at lower temperature (P₂) = 330 W.
To find:
a. Electric current (I₁) at higher temperature.
b. Electric current (I₂) at lower temperature.
c. Resistance (R₁) at higher temperature
d. Resistance (R₂) at lower temperature,
Formulae:
a. P = VI b. V = IR
Calculation :
For higher temperature,
From formula (a),

For lower temperature,

Ans:
a. Electric current at higher temperature is 5 A.
b. Electric current at lower temperature is 1.5 A.
c. Resistance at higher temperature is 44 Ω.
d. Resistance at lower temperature is 146.67 Ω.

iii. Depending on their functions, satellites are classified into following categories:
a. Weather satellite: These satellites are used to study and forecast weather conditions on the earth.
b. Communication satellite: These satellites use specific waves to establish communication between different locations in the world.
c. Broadcast satellite: These satellites are used to telecast different television programs all over the world.
d. Navigational satellite: These satellites help in locating any place on earth’s surface by filing the location in terms of its precise latitude and longitude.
e. Military satellite: These satellites collect information for security aspects of nation.
f. Earth observation satellite: These satellites are used in the study of forests, deserts, oceans, polar ice on Earth’s surface. These are also used in exploration and management of natural resources. They also collect information which guides us in case of natural calamities like flood and earthquake.

iv. Oxidation is the process in which a substance gains oxygen or loses hydrogen. Reduction is the process in which a substance gains hydrogen or loses oxygen. The reaction in which one reactant gets oxidised and the other reactant or the same reactant gets reduced is called as oxidation-reduction reaction or redox reaction. Oxidation and reduction reactions always occur simultaneously.
(Note: In ‘Complete the paragraph’, students are expected to rewrite the completed paragraph and underline the answers.)

v. a. Consider a stone thrown vertically upwards with initial velocity ‘u’. It reaches a height ’h’ before coming down.
b. The kinematical equations of motion are given as,
v = u + at ….(1)
s = ut + \(\frac{1}{2}\)at² ….(2)
v² – u² = 2as ….(3)

c. For upward motion of the stone,
a = – g (negative sign indicates the direction of force is opposite to that of velocity.)
v = 0 (∵ at the highest point velocity becomes zero).
Substituting this in equation (1), the time ti taken by the stone to reach the maximum height is given as,
O = u – gt₁
∴ t₁ = \(\frac{u}{g}\)
Similarly, substituting the values of a and v in equation (3), the maximum height h which the stone reaches is given as,
O² – u² = -2gh
∴ h = \(\frac{u^2}{2g}\)
For downward motion of the stone,
a = g
u = O (∵ at maximum height, initial velocity is zero.)
Substituting this in equation (2), the time t2 taken by the stone to reach the maximum height is given as,

Thus, from equations (4) and (7), t₁ = t₂.
Hence, we can conclude that the time taken by the stone to go up is same as the time taken to come down.

vi.

SMART TIP
Each circle represents shell. The electrons in outermost circle are valence electrons

vii. a. The given picture represents the electrochemical reaction taking place during the corrosion (rusting) of iron.
b. Different regions on the surface of iron become anode and cathode.
c. In the anode region, Fe is oxidized to Fe
Fe_(S) → Fe²⁺_(aq) + 2e^–
d. The electron released in the anode region flow through the metal surface to the cathode region where they reduce oxygen.
In the cathode region, 02 is reduced to form water.
O_2(g) + 4H⁺_(aq) + 4e^– → 2H₂O_(l)
e. When Fe²⁺ ions migrate from the anode region, they react with water (or OH^– ions) and further get oxidized to Fe³⁺ ions.
f. Fe³⁺ions form an insoluble hydrated oxide (Fe2C>3.H20), which is deposited as reddish brown layer on the surface. It is called rust.

Viii. a. Convex lens
b. Magnification
c. Iris
d. Presbyopia
e. Astronomical telescope
f. Persistence of vision

Question 4.
Answer the following. (Attempt any 1) [5]
i. Carbon forms a large number of compounds because of its two unique properties catenation and tetravalency. The compounds formed may have long straight chains of carbon, branched chains of carbon or rings of carbon. In these compounds, carbon atoms may form single, double or triple covalent bonds. Compounds in which the carbon atoms are linked to each other by single bonds are called saturated carbon compounds whereas compounds having at least one carbon-carbon double or triple bond are called unsaturated carbon compounds. Compounds containing only carbon and hydrogen are known as hydrocarbons. Based on the above information, answer the following questions.
a. Why does carbon form large number of compounds?
b. Give two examples of carbon compounds which have ring structure.
c. What are saturated hydrocarbons? Give one example.
d. Give IUPAC names of first two members of hydrocarbon which contain carbon-carbon double bonds.
e. What is common name and molecular formula of ethyne?
ii. Calculate the missing terms and complete the following table.

Answer:
i. a. Carbon forms large number of compounds because of its two unique properties catenation and tetravalency.
b. Benzene and cyclohexane are the two examples of carbon compounds having ring structure.
c. Hydrocarbons in which the carbon atoms are linked to each other by single bonds is called saturated hydrocarbons.
E.g. Methane (CH4)
d. The IUPAC names of first two members of hydrocarbon which contain carbon-carbon double bonds are ethene and propene.
e. The common name of ethyne is acetylene. Its molecular formula is C2H2. [5 Marks]

ii. Solution:

SSC Maharashtra Board Science 1 Question Paper with Solutions