Maharashtra Board 8th Class Maths Practice Set 10.1 Solutions Chapter 10 Division of Polynomials

Balbharti Maharashtra State Board Class 8 Maths Solutions covers the Practice Set 10.1 8th Std Maths Answers Solutions Chapter 10 Division of Polynomials.

Practice Set 10.1 8th Std Maths Answers Chapter 10 Division of Polynomials

Question 1.
Divide and write the quotient and the remainder.
i. 21m² ÷ 7m
ii. 40a³ ÷ (-10a)
iii. (- 48p4) ÷ (- 9p2)
iv. 40m5 ÷ 30m3
v. (5x3 – 3x2) ÷ x²
vi. (8p3 – 4p2) ÷ 2p2
vii. (2y3 + 4y2 + 3 ) ÷ 2y2
viii. (21x4 – 14x2 + 7x) ÷ 7x3
ix. (6x5 – 4x4 + 8x3 + 2x2) ÷ 2x2
x. (25m4 – 15m3 + 10m + 8) ÷ 5m3
Solution:
i. 21m² ÷ 7m
Maharashtra Board Class 8 Maths Solutions Chapter 10 Division of Polynomials Practice Set 10.1 1
∴ Quotient = 3m
Remainder = 0

ii. 40a³ ÷ (-10a)
Maharashtra Board Class 8 Maths Solutions Chapter 10 Division of Polynomials Practice Set 10.1 2
∴ Quotient = -4a²
Remainder = 0

iii. (- 48p4) ÷ (- 9p2)
Maharashtra Board Class 8 Maths Solutions Chapter 10 Division of Polynomials Practice Set 10.1 3
∴ Quotient = \(\frac { 16 }{ 3 }\) p²
Remainder = 0

iv. 40m5 ÷ 30m3
Maharashtra Board Class 8 Maths Solutions Chapter 10 Division of Polynomials Practice Set 10.1 4
∴ Quotient = \(\frac { 4 }{ 3 }\) m²
Remainder = 0

v. (5x3 – 3x2) ÷ x²
Maharashtra Board Class 8 Maths Solutions Chapter 10 Division of Polynomials Practice Set 10.1 5
∴ Quotient = 5x – 3
Remainder = 0

vi. (8p3 – 4p2) ÷ 2p2
Maharashtra Board Class 8 Maths Solutions Chapter 10 Division of Polynomials Practice Set 10.1 6
∴ Quotient = 4p – 2
Remainder = 0

vii. (2y3 + 4y2 + 3 ) ÷ 2y2
Maharashtra Board Class 8 Maths Solutions Chapter 10 Division of Polynomials Practice Set 10.1 7
∴ Quotient = y + 2
Remainder = 3

viii. (21x4 – 14x2 + 7x) ÷ 7x3
Maharashtra Board Class 8 Maths Solutions Chapter 10 Division of Polynomials Practice Set 10.1 8
∴ Quotient = 3x
Remainder = -14x² + 7x

ix. (6x5 – 4x4 + 8x3 + 2x2) ÷ 2x2
Maharashtra Board Class 8 Maths Solutions Chapter 10 Division of Polynomials Practice Set 10.1 9
∴ Quotient = 3x³ – 2x² + 4x + 1
Remainder = 0

x. (25m4 – 15m3 + 10m + 8) ÷ 5m3
Maharashtra Board Class 8 Maths Solutions Chapter 10 Division of Polynomials Practice Set 10.1 10
∴ Quotient = 5m – 3
Remainder = 10m + 8

Maharashtra Board Class 8 Maths Chapter 10 Division of Polynomials Practice Set 10.1 Intext Questions and Activities

Question 1.
Fill in the blanks in the following examples. (Textbook pg. no. 61)

  1. 2a + 3a = __
  2. 7b – 4b = __
  3. 3p × p² = __
  4. 5m² × 3m² = __
  5. (2x + 5y) × \(\frac { 3 }{ x }\) = __
  6. (3x² + 4y) × (2x + 3y) = __

Solution:

  1. 2a + 3a = 5a
  2. 7b – 4b = 3b
  3. 3p × p² = 3p³
  4. 5m² × 3m² = 15m4
  5. (2x + 5y) × \(\frac { 3 }{ x }\) = \(6+\frac { 15y }{ x }\)
  6. (3x² + 4y) × (2x + 3y) = 6x³ + 9x²y + 8xy + 12y²

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