# Maharashtra Board Class 5 Maths Solutions Chapter 16 Preparation for Algebra Problem Set 56

Balbharti Maharashtra Board Class 5 Maths Solutions Chapter 16 Preparation for Algebra Problem Set 56 Textbook Exercise Important Questions and Answers.

## Maharashtra State Board Class 5 Maths Solutions Chapter 16 Preparation for Algebra Problem Set 56

Question 1.
Use a letter for ‘any number’ and write the following properties in short.

(1) The sum of any number and zero is the number itself.
a + 0 = a (2) The product of any two numbers and the product obtained after changing the order of those numbers is the same.
a x b = b x a

(3) The product of any number and zero is zero.
a x 0 = 0

Question 2.
Write the following properties in words :

(1) m – 0 = m
Subtracting zero from any number, gives the number itself.

(2) n ÷ 1 = n
Dividing any number by 1, gives the number itself.

Use a letter for any number and write the following properties in short.

Question 1.
The product of any number and 1 is the number itself.
a x 1 = a Question 2.
The division of any two different numbers and the divisions obtained after changing the order of those numbers is not the same.
a ÷ b ≠ b + a

Write the following properties in words:

Question 1.
p x 0 = 0
The product of any number and zero is zero.

(4) a + b = b + a
The sum of any two numbers and the sum obtained after changing the order of these numbers is the same.

Using brackets write three pairs of numbers whose

(1) Sum is 9
5 + 4 = 9,
7 + 2 = 9,
8 + 1 = 9 (2) difference is 9
12 – 3 = 9,
11 – 2 = 9,
10 – 1 = 9

(3) multiplication is 16 and
4 x 4 = 16,
8 x 2 = 16,
16 x 1 = 16

(4) division is 16.
32 ÷ 2 = 16,
48 ÷ 3 = 16,
64 ÷ 4 = 16,

Fill in the blanks.

(1) 4 + 2 = 7 – ……….
(2) 4 + 2 = 3 x ……….
(3) 4 + 2 = 12 ÷ ……….
(1) 1
(2) 2
(3) 2 Match the columns:

(A)

 A B (i) 8 + 6 (a) 6 x 2 (2) 9 + 3 (b) 6 + 2 (3) 5 + 1 (c) 16 – 2 (4) 10 – 2 (d) 12 + 2

(1 – c),
(2 – a),
(3-d),
(4-b)

(B)

 A B (1) a – b and b – a (a) 0 (2) a x b and b x a (b) 1 (3) a x 0 (c) = (4) a + a (d) ≠

(1-d),
(2 – c),
(3 – a),
(4 – b) Say whether right or wrong.

(1) (6 + 5) = (5 + 6)
(2) (8 + 5) > 10
(3) (8 + 5) < 10
(4) 108 > 108
(5) 108 = 108
(6) 108 < 108
(7) (6 x 3) = (20 – 2)
(8) 40 + 8 > 5
(9) (3 x 7) = (7 x 3)
(10) (5 + 0) = (5 x 1)
(11) (6 + 5) = 10
(12) (30 + 5) < (30 – 25)
Right : (1), (2), (5), (7), (9), (10)
Wrong : (3), (4), (6), (8), (11), (12)

Fill in the blanks with the right symbol from <, > or =

(1) (24 ÷ 5) ……… (9 – 5)
(2) (4 + 2) ……… (5 x 1)
(3) (7 x 3) ……… (20 + 2)
(4) (8 x 2) (5 x 3)
(5) (5 x 6) ……… (25 + 5)
(6) (6 x 7) (9 x 5)
(1) =
(2) >
(3) <
(4) >
(5) =
(6) < Fill in the blanks in the expressions with the proper numbers.

(1) (4 x 4) = (………. x 2)
(2) (2 x 7) > (4 x ……….)
(3) (30 + 5) < ( x 3)
(4) (5 + 0)> (4 x ……….)
(5) (36 +3) = ( + )
(6) (9 – ……….) < (4 + 1)
(7) (8 + 9) < (3 x ……….)
(8) (0 + 3) > (4 x ……….)
(9) (28 ÷ 2) = (7 x ……….)
(1) 8
(2) 3
(3) 9
(4) 1
(5) 7 + 5
(6) 5,
(7) 6
(8) 0
(9) 2

Use a letter for any number and write the following properties in short:

(1) Dividing zero by any non zero number is zero.
0 + a = 0 (2) The difference of any two different numbers and the difference obtained after changing the order of those numbers is not same.
a – b ≠ b – a

(3) Dividing non zero number by itself gives us 1.